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AP Physics 2 · Unit 15 · Topic 4 of 5 · 5 min lesson

Wave–Particle Duality

A short lesson with diagrams, a worked example, a problem to try, and a quick check. Then quiz yourself on 5 practice questions.

The big idea

Light and matter both act like waves and like particles. Light interferes (wave) but delivers energy in photons (particle). Electrons arrive as single dots (particle) but build up interference patterns (wave). Every moving object has a de Broglie wavelength, λ = h/p.

1. Matter waves

e⁻ one at a time two slits detector each lands as a dot together: fringes
Fire electrons one at a time through two slits: each hits like a particle, but where they land follows a wave’s interference pattern.
λ = h/p = h/(mv)de Broglie wavelength
Bigger momentumshorter wavelength
Electrons through crystalsdiffraction: wave evidence
Photoelectric effectparticle evidence for light

2. Why we don’t notice

Waves only show their wave behavior when they pass through openings or around objects about their own size.

An electron’s wavelength is about the spacing of atoms in a crystal, so crystals diffract electrons. A baseball’s wavelength is far smaller than anything it could pass through.

Electron microscopes use this: electrons’ tiny wavelengths let them see detail much finer than visible light can.

A photon and an electron with the same wavelength have the same momentum, p = h/λ.

3. Example, then try it

Example

Find the de Broglie wavelength of an electron (9.11 × 10⁻³¹ kg) at 2.0 × 10⁶ m/s, and of a 0.145 kg baseball at 40 m/s.

Electron: λ = (6.63 × 10⁻³⁴) ÷ [(9.11 × 10⁻³¹)(2.0 × 10⁶)] ≈ 3.6 × 10⁻¹⁰ m, about atom-sized.

Baseball: λ = (6.63 × 10⁻³⁴) ÷ [(0.145)(40)] ≈ 1.1 × 10⁻³⁴ m, far too small to detect.

Try it · work it on paper first

An electron starts from rest and is accelerated through 150 V. Find its kinetic energy, speed and de Broglie wavelength. Would it diffract off a crystal with atoms about 10⁻¹⁰ m apart?

1

Kinetic energy: K = qΔV = 150 eV = (150)(1.6 × 10⁻¹⁹) = 2.4 × 10⁻¹⁷ J.

2

Speed: v = √(2K/m) = √(2 × 2.4 × 10⁻¹⁷ ÷ 9.11 × 10⁻³¹) ≈ 7.3 × 10⁶ m/s.

3

Wavelength: λ = h/(mv) = (6.63 × 10⁻³⁴) ÷ [(9.11 × 10⁻³¹)(7.3 × 10⁶)] ≈ 1.0 × 10⁻¹⁰ m.

4

Diffraction: yes. Its wavelength matches the atom spacing.

Answer: 150 eV, 7.3 × 10⁶ m/s, 1.0 × 10⁻¹⁰ m; it diffracts.

4. Common mistakes

“Only light has a wavelength.”Every moving object has λ = h/p.
“Heavier means longer wavelength.”More momentum means a shorter wavelength.
Picking one model.Neither picture alone explains all the experiments; both are needed.
Check yourself

Why don’t we see a thrown baseball diffract through a doorway?

λ = h/(mv) is about 10⁻³⁴ m for a baseball, much too small compared with a doorway for any diffraction to show.

Ready to practice?

5 questions on Wave–Particle Duality, each with a hint and an explanation for every wrong answer.

Unit 15 topics

Every topic has a short lesson or quick review and its own quiz.