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AP Physics 1 · Unit 2 · Topic 8 of 9 · 6 min lesson

Circular Motion

A short lesson with diagrams, a worked example, a problem to try, and a quick check. Then quiz yourself on 5 practice questions.

The big idea

Moving in a circle at constant speed is still accelerating, because the direction of the velocity keeps changing. The acceleration points toward the center with size v²/r. Something real has to supply that inward net force, mv²/r: a string, friction, gravity, or a normal force.

1. Velocity along, acceleration in

v v a a v: along the circle a and Fnet: toward the center
The velocity is always tangent to the circle. The acceleration and net force always point to the center.
ac = v² ÷ rtoward the center
Fnet = mv² ÷ rtoward the center
v = 2πr ÷ TT = time for one lap

2. “Centripetal” isn’t a new force

Centripetal force is a job, not a new kind of force. Ask which real force points toward the center:

A ball on a string: tension. A car on a flat curve: static friction from the road. The Moon around Earth: gravity.

There is no outward “centrifugal” force on the free-body diagram. You feel thrown outward on a turn because your body tries to keep going straight while the car turns.

Since a = v²/r, doubling the speed makes the needed force four times as large.

3. Example, then try it

Example

A 1200 kg car rounds a flat curve of radius 50 m at 10 m/s. How much friction must the road supply?

Fnet = mv²/r = (1200)(10²) ÷ 50 = 2400 N, pointing toward the center of the curve.

That is static friction: the tires grip without sliding sideways.

Try it · work it on paper first

A 0.50 kg ball on a 0.80 m string is swung in a vertical circle. At the lowest point it moves at 4.0 m/s. Find the tension there. (g = 10 m/s²)

1

Center is straight up, so take up as + and the net force must point up.

2

Needed acceleration: a = v²/r = 16 ÷ 0.80 = 20 m/s² upward.

3

Forces: tension up, weight down: FT − mg = ma.

4

Solve: FT = m(g + a) = 0.50(10 + 20) = 15 N.

Answer: 15 N, three times the ball’s 5 N weight.

4. Common mistakes

Drawing a centrifugal force.No outward force acts on the object. The net force points inward.
Adding “Fc” as an extra arrow.The centripetal force is the net of the real forces you already drew.
“Constant speed means no acceleration.”The direction changes, so the velocity changes. That is acceleration.
Check yourself

A ball on a string moves in a horizontal circle. Suddenly the string breaks. Which way does the ball go?

Once the string breaks, nothing pulls it inward, so it keeps moving in a straight line in the direction it was going at that instant: along the tangent.

Ready to practice?

5 questions on Circular Motion, each with a hint and an explanation for every wrong answer.

Unit 2 topics

Every topic has a short lesson or quick review and its own quiz.